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2x^2+51x-115=0
a = 2; b = 51; c = -115;
Δ = b2-4ac
Δ = 512-4·2·(-115)
Δ = 3521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-\sqrt{3521}}{2*2}=\frac{-51-\sqrt{3521}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+\sqrt{3521}}{2*2}=\frac{-51+\sqrt{3521}}{4} $
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